{"id":34935,"date":"2025-02-24T11:05:17","date_gmt":"2025-02-24T11:05:17","guid":{"rendered":"https:\/\/mp.moonpreneur.com\/math-corner\/?p=34935"},"modified":"2025-02-24T11:22:35","modified_gmt":"2025-02-24T11:22:35","slug":"sat-prep-mock-test-4-math-mistakes","status":"publish","type":"post","link":"https:\/\/mp.moonpreneur.com\/math-corner\/sat-prep-mock-test-4-math-mistakes\/","title":{"rendered":"My SAT Prep Journey: The Question I Got Wrong in Mock Test 4"},"content":{"rendered":"\t\t
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SAT preparation has been really<\/span> tough<\/span> for me with <\/span>lots of ups and downs and<\/span> lots<\/span> of learning. Let’s <\/span>talk<\/span> about <\/span>my SAT prep <\/span>experience<\/span>: what I did, where I <\/span>struggled<\/span> and how I <\/span>overcame<\/span> all the <\/span>obstacles that came in my way. Believe me If I could<\/span> do<\/span> it<\/span>, then you can <\/span>also do it<\/span>. So, let’s <\/span>start<\/span>.<\/span><\/p>

First <\/span>of<\/span> all<\/span>, I was <\/span>too<\/span> keen<\/span> on<\/span> getting<\/span> a good score <\/span>in the SAT exam. So, I began<\/span> preparing<\/span> for that. I <\/span>prepared hard at my own level and I was too happy at that time and felt<\/span> that I am <\/span>well<\/span> prepared to <\/span>appear<\/span> for <\/span>the SAT exam. <\/span>Therefore<\/span>, I <\/span>considered<\/span> taking the SAT Mock Test provided<\/span> on the official website because I was<\/span> quite<\/span> sure that mock tests would be the deciding<\/span> factor <\/span>in <\/span>determining<\/span> where I <\/span>was standing<\/span>. So, I <\/span>start<\/span> with Math <\/span>on the SAT Mock Test 4 and guess what? This test taught me a lesson which I hadn<\/span>‘t <\/span>anticipated<\/span>.\u00a0<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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My Mock Test 4 Experience<\/b><\/h3>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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When I began<\/span>, I <\/span>realized that the questions were relatively<\/span> simple<\/span> and <\/span>easy<\/span> to<\/span> manage<\/span> initially <\/span>but <\/span>when<\/span> I <\/span>progressed further, the questions were becoming<\/span> difficult<\/span> for me to <\/span>solve<\/span> and at that <\/span>time<\/span>, I <\/span>began<\/span> losing my confidence. <\/span>Nonetheless<\/span>, I <\/span>finished both modules as this would assist<\/span> me in <\/span>identifying<\/span> my weak <\/span>points<\/span> where I could <\/span>work upon<\/span>.<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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Now<\/span> this is the time when I went<\/span> through <\/span>my answers and the <\/span>outcome<\/span> was <\/span>really shocking for me. I was able to get 530 in Module1 and 530 in Module2. Since<\/span> I was <\/span>anticipating<\/span> a <\/span>better<\/span> score, I <\/span>began<\/span> going<\/span> through <\/span>the answers to <\/span>know<\/span> where I <\/span>went wrong.<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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The Question I Got Wrong<\/b><\/h3>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Let<\/span>‘<\/span>s <\/span>talk<\/span> about the questions <\/span>that <\/span>I <\/span>answered<\/span> incorrectly from both modules and the challenges<\/span> that <\/span>I <\/span>encountered<\/span> in<\/span> solving them.<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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From Module 1:<\/span><\/strong><\/h3>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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\n\t\t\t \r\n 1. Hana deposited a fixed amount into her bank account each month. \r\n The function \\(f(t) = 100 + 25t\\) gives the amount, in dollars, \r\n in Hana's bank account after \\(t\\) monthly deposits. \r\n What is the best interpretation of \\(25\\) in this context? \r\n<\/b>\r\n\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\n A) With each monthly deposit, the amount in Hana's bank account increased by $\\(25\\).
\r\n B) Before Hana made any monthly deposits, the amount in her bank account was $\\(25\\).
\r\n C) After \\(1\\) monthly deposit, the amount in Hana's bank account was $\\(25\\).
\r\n D) Hana made a total of \\(25\\) monthly deposits.\r\n<\/div>\r\n\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Linear functions. My Answer: D) but the correct answer is A). While reading this question, I didn\u2019t give much time to understand the question and due to my negligence, I ended up selecting the wrong answer.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 2. Right triangles \\(PQR\\) and \\(STU\\) are similar, where \\(P\\)\r\ncorresponds to \\(S\\). If the measure of angle \\(Q\\) is \\(18^\\circ\\),\r\nwhat is the measure of angle \\(S\\) ? <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(18^\\circ\\)
\r\nB) \\(72^\\circ\\).
\r\nC) \\(82^\\circ\\).
\r\nD) \\(162^\\circ\\) \r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Lines, angles, and triangles. My Answer: A) but the correct answer is B). While solving this question, I realized that my concepts on this topic were not strong enough which made me give the wrong answer.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 3. The scatterplot shows the relationship between two variables, \\(x\\) and \\(y\\) \r\n<\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\n\t\t\t Which of the following equations is the most\r\nappropriate linear model for the data shown ?<\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(y=0.9+9.4x\\)
\r\nB) \\(y=0.9-9.4x\\).
\r\nC) \\(y=9.4+0.9x\\).
\r\nD) \\(y=9.4-0.9x\\)\r\n<\/div>\r\n\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Two-variable data. My Answer: A) but the correct answer is D). While solving this question, I realized that my concepts on this topic were not strong enough which made me give the wrong answer.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t\t\t\t\t\t\t\t\t\t\"Sat\t\t\t\t\t\t\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\n\t\t\t 4. What is an equation of the graph shown ?<\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(y=-2x-8\\)
\r\nB) \\(y=x-8\\).
\r\nC) \\(y=-x-8\\).
\r\nD) \\(y=2x-8\\) \r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Linear equations in two variables. My Answer: A) but the correct answer is C). Honestly, this question was not that hard but I didn\u2019t pay much attention to the details and regretted it later as my concepts were clear for this question.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 5. \\(\\frac{\\Large 14x}{\\Large 7y}= 2\\sqrt{w+19}\\)
The given equation relates the distinct positive real\r\nnumbers \\(w\\), \\(x\\), and \\(y\\). Which equation correctly\r\nexpresses \\(w\\) in terms of \\(x\\) and \\(y\\) ? \r\n<\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(w=\\sqrt{\\frac{\\Large x}{\\Large y}}-19\\).

\r\nB) \\(w=\\sqrt{\\frac{ \\Large 28x}{\\Large 14y}}-19\\).

\r\nC) \\(w = \\left(\\frac{\\Large x}{\\Large y}\\right)^2 - 19\\).

\r\nD) \\(w = \\left(\\frac{\\Large 28x}{\\Large 14y}\\right)^2 - 19\\).\r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Equivalent expressions. My Answer: A) but the correct answer is C). Honestly, this question was not that hard but I realized that I made a calculation mistake at the last step which made my whole answer incorrect.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 6. Point \\(O\\) is the center of a circle. The measure of\r\narc \\(RS\\) on this circle is \\(100^\\circ\\). What is the measure, in\r\ndegrees, of its associated angle \\(ROS\\) ? \r\n<\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

This question comes from the category: Circles. I didn\u2019t attempt this question as I was completely clueless about the method of solving this question.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 7. [The expression \\(6^5\\sqrt{ 3^5 x^{45}}. \\sqrt[8]{2^8x}\\)\r\nis equivalent to \\(ax^b\\) ,\r\nwhere \\(a\\) and \\(b\\) are positive constants and \\(x > 1\\).\r\nWhat is the value of \\(a + b\\) ?<\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Equivalent expressions. This question was also not difficult to attempt but I didn\u2019t give much time to this question because of the limited time. So, I skipped that question too.\u00a0<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 8. A right triangle has sides of length \\(2\\sqrt{2}\\), \\(6\\sqrt{2}\\), and \\(\\sqrt{80}\\) units.What is the area of the triangle, in square units ? <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(8\\sqrt{2} + \\sqrt{80}\\).
\r\nB) \\(12\\).
\r\nC) \\(24\\sqrt{80}\\).
\r\nD) \\(24\\).\r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Right triangles and trigonometry. This question was also not difficult to attempt but I didn\u2019t give much time to this question because of the limited time. So, I skipped that question too.\u00a0<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 9. In the \\(xy\\)-plane, a parabola has vertex \\((9, -14)\\) and\r\nintersects the \\(x\\)-axis at two points. If the equation of\r\nthe parabola is written in the form \\(y = ax^2 + bx + c\\),\r\nwhere \\(a\\), \\(b\\), and \\(c\\) are constants, which of the\r\nfollowing could be the value of \\(a\\)+ \\(b\\) + \\(c\\) ?\r\n <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(-23\\).
\r\nB) \\(-19\\).
\r\nC) \\(-14\\).
\r\nD) \\(-12\\).\r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Linear functions. My Answer: D) but the correct answer is A). While reading this question, I didn\u2019t give much time to understand the question and due to my negligence, I ended up selecting the wrong answer.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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From Module 2:<\/span><\/strong><\/h3>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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\n\t\t\t 10. Which expression is equivalent to \\(12x^3-5x^3\\) ?\r\n <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(7x^6\\).
\r\nB) \\(17x^3\\).
\r\nC) \\(7x^3\\).
\r\nD) \\(17x^6\\).\r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Can you believe it?..Someone who is preparing for the SAT can give the wrong answer to this question? But, I did. Yes, I admit my mistake that due to my negligence and limited time, I panicked and ended up giving the wrong answer, even to this question. Unbelievable!!<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 11. A proposal for a new library was included on an election ballot. A radio show stated that 3 times as many people voted in favor of the proposal as people who voted against it. A social media post reported that 15,000 more people voted in favor of the proposal than voted against it. Based on these data, how many people voted against the proposal? <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(7,500\\).
\r\nB) \\(15,000\\).
\r\nC) \\(22,500\\).
\r\nD) \\(45,000\\).\r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now, this question comes from the category: Linear Equations in Two Variables. My Answer: D) but the correct answer is A). I found this question a little complicated to understand which made me give the wrong answer.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 12. \\(f(x)=(x-10)(x+13)\\)

The function \\(f\\) is defined by the given equation. For\r\nwhat value of \\(x\\) does \\(f(x)\\) reach its minimum ? <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(-130\\).

\r\nB) \\(-13\\).

\r\nC) \\(-\\frac{\\Large 23}{\\Large 2}\\).

\r\nD) \\(-\\frac{\\Large 3}{\\Large 2}\\).\r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

This question was based on Calculus and I was completely aware of the concept, even I applied it too. but I realized that I made a calculation mistake at the last step which made my whole answer incorrect. My Answer: A) but the correct answer is D). You know, it feels very bad when you know how to solve the question but end up making a calculation mistake. A regretful moment for me.<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 13. The function \\(f(x)=\\frac{\\Large 1}{\\Large 9}(x-7)^2+3\\) gives a metal\r\nBall's height above the ground \\(f(x)\\), in inches,\r\n\\(x\\) seconds after it started moving on a track, where \\(0\\leq x\\leq10\\). Which of the following is the best interpretation of the vertex of the graph of \\(y=f(x)\\) in the \\(xy\\)-plane ?<\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) The metal ball's minimum height was \\(3\\) inches\r\nabove the ground.
\r\nB) The metal ball's minimum height was \\(7\\) inches above the ground.
\r\nC) The metal ball's height was \\(3\\) inches above the ground when it started moving.
\r\nD) The metal ball's height was \\(7\\) inches above the\r\nground when it started moving. \r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

This question was also not difficult to attempt but I didn\u2019t give much time to this question because of the limited time. So, I skipped that question.\u00a0<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 14. If a new graph of three linear equations is created\r\nusing the system of equations shown and the\r\nequation \\(x + 4y = -16\\), how many solutions \\((x,y)\\)\r\nwill the resulting system of three equations have ? <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\n\t\t\t\t\t\t\t\t\t\t\t\t\"Sat\t\t\t\t\t\t\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) Zero
\r\nB) Exactly One
\r\nC) Exactly two
\r\nD) Infinitely many\r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

To be honest, I was not completely sure about the answer of this question, so I made a quick guess and guess what? I guessed it wrong. My Answer: B) but the correct answer is A).\u00a0<\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 15. \\(f(x)=5,470(0.64)^\\frac{\\Large x}{\\Large 12}\\)

The function \\(f\\) gives the value, in dollars, of a certain piece of equipment after \\(x\\) months of use. If the\r\nvalue of the equipment decreases each \\(\\underline{year}\\) by \\(p\\%\\) of\r\nits value the preceding year, what is the value of \\(p\\) ? <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(4\\)
\r\nB) \\(5\\)
\r\nC) \\(36\\)
\r\nD) \\(64\\) \r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

This question was taking me time to grasp the exact concept of this question and due to limited time. So, I skipped that question.\u00a0<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 16. The equation \\(x^2+(y-1)^2=49\\) represents circle \\(A\\).\r\nCircle \\(B\\) is obtained by shifting circle \\(A\\) down \\(2\\) units\r\nin the \\(xy\\)-plane. Which of the following equations\r\nrepresents circle \\(B\\) ? <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\((x-2)^2+(y-1)^2=49\\)
\r\nB) \\(x^2+(y-3)^2=49\\).
\r\nC) \\((x+2)^2+(y-1)^2=49\\)
\r\nD) \\(x^2+(y+1)^2=49\\)\r\n<\/div>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Explanation<\/b><\/span><\/h5>

Now while solving this question, I was pretty sure that my answer would be right as I have already practiced these types of questions earlier, but this was a time of reality check. My answer was incorrect, even I was disappointed. Probably, my concepts were still not strong at that time.\u00a0<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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\n\t\t\t 17. Two identical rectangular prisms each have a height\r\nof \\(90\\) centimeters \\((cm)\\). The base of each prism is a\r\nsquare, and the surface area of each prism is \\(K cm^2\\) .\r\nIf the prisms are glued together along a square base,\r\nthe resulting prism has a surface area of \\(\\frac{\\Large 92}{\\Large 47}K cm^2\\)\r\nWhat is the side length, in \\(cm\\), of each square base ? <\/b>\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\r\nA) \\(4\\)
\r\nB) \\(8\\).
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Explanation<\/b><\/span><\/h5>

This question was taking me time to grasp the exact concept of this question and due to limited time. So, I skipped that question.\u00a0<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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What I Learned from My Mistakes<\/b><\/h3>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Honestly, these mistakes discouraged me a little while reviewing the correct answers. But, it was a reminder that confidence can sometimes lead to carelessness. I realized that overconfidence can be just as dangerous as lack of knowledge. Every detail matters, and I needed to train myself to double-check, even when I was sure I was right.\u00a0<\/span><\/p>

The main lesson I learned? <\/span>Slow down and read carefully<\/b>, especially on questions that seem straightforward at first.\u00a0<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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Measures Taken By Me To Improve My Practice and Overall Score<\/b><\/h4>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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After taking Mock Test 4, I made some changes in my preparation strategy. First, I started practicing similar problems on topics:<\/span> Circles, Right triangles and trigonometry, Power and Indices and Algebraic Expressions, and Linear equations in two variables<\/b> to have a strong grip of these concepts into my brain. As there were some questions which I might be able to crack but due to limited time, I skipped them. So, I also worked on Time Management. I began solving questions by setting the timer to ensure accuracy over speed. Now, my new motive is: <\/span>slow is smooth, and smooth is fast.<\/span><\/i><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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Additionally, I began reviewing every question I got right and wrong after giving each mock test which helps me realize where I am improving. Sometimes, the questions you get right by guessing or rushing are the ones you need to revisit the most. This approach helped me identify my small mistakes before they became big problems on test day.<\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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Additional Resources Which Helped Me in My SAT Prep Journey<\/b><\/h4>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t
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Beyond mock tests, there were some other resources as well which played a crucial role in my SAT preparation journey and helped me improve my score. Check out these extra resources:<\/span><\/p>